Math, asked by tulighosh2612, 5 hours ago

The total age of father and son is 86 years, 10 years ago the age of father was twice the age of son, what is the age of father now​

Answers

Answered by rudrauparkar
0

Answer:

54 yrs

Step-by-step explanation:

Let son's present age = x year

Total age of father and son = 86

So, Father's present age = 86 - x

10 years ago,

Son's age = x - 10

Father's age = ( 86 - x ) - 10

= 76 - x

10 years ago father's age was twice the age of son

i.e. ( 76 - x) = 2 ( x - 10)

76 - x = 2 x - 20

76 + 20 = 2x + x

3x = 96

x =. 96 / 3

x = 32 yrs

Father's age now = 86 - x

= 86 - 32

= 54 yrs

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