The total age of father and son is 86 years, 10 years ago the age of father was twice the age of son, what is the age of father now
Answers
Answered by
0
Answer:
54 yrs
Step-by-step explanation:
Let son's present age = x year
Total age of father and son = 86
So, Father's present age = 86 - x
10 years ago,
Son's age = x - 10
Father's age = ( 86 - x ) - 10
= 76 - x
10 years ago father's age was twice the age of son
i.e. ( 76 - x) = 2 ( x - 10)
76 - x = 2 x - 20
76 + 20 = 2x + x
3x = 96
x =. 96 / 3
x = 32 yrs
Father's age now = 86 - x
= 86 - 32
= 54 yrs
Similar questions