the total cost of three tables3 and 2 chairs is 8745 if a table cost 40 rupees more than a chair find the price of each
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Answered by
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Here is your solutions
Given:-
The total cost of three tables 3 and 2 chairs is 8745.
Let
The cost of 1 chair be x.
The cost of 1 table will be x+40.
To find cost of each is needed:-
Equation will be 2x+3(x+40)
A/q
2x+3x+120=8745
5x+120 = 8745
5x=8745-120
x=8625/5=1725
Hence
Cost of 1 chair = x = Rs 1725 .
Cost of 1 table=x+40=1725+40=1765
Hope it helps you
Given:-
The total cost of three tables 3 and 2 chairs is 8745.
Let
The cost of 1 chair be x.
The cost of 1 table will be x+40.
To find cost of each is needed:-
Equation will be 2x+3(x+40)
A/q
2x+3x+120=8745
5x+120 = 8745
5x=8745-120
x=8625/5=1725
Hence
Cost of 1 chair = x = Rs 1725 .
Cost of 1 table=x+40=1725+40=1765
Hope it helps you
SmãrtyMohït:
thanks
Answered by
42
Solutions :-
Given :
3 tables and 2 chairs cost = Rs 8745
Let the cost of 1 chair be x
Cost of 1 table = x + 40
A/q
=> 2x + 3(x + 40) = 8745
=> 2x + 3x + 120 = 8745
=> 5x = 8745 - 120
=> 5x = 8625
=> x = 8625/5 = 1725
Hence,
Cost of 1 chair = x = Rs 1725
Cost of 1 table = x + 40 = Rs (1725 + 40) = Rs 1765
Given :
3 tables and 2 chairs cost = Rs 8745
Let the cost of 1 chair be x
Cost of 1 table = x + 40
A/q
=> 2x + 3(x + 40) = 8745
=> 2x + 3x + 120 = 8745
=> 5x = 8745 - 120
=> 5x = 8625
=> x = 8625/5 = 1725
Hence,
Cost of 1 chair = x = Rs 1725
Cost of 1 table = x + 40 = Rs (1725 + 40) = Rs 1765
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