Question

The total energy of a particle of mass 200 gram performing SHM is 10 power minus 3 find its maximum velocity and period if the amplitude is 5 cm

Answer 1

Answer:

maximum speed of SHM is 0.1 m/s and its time period is 3.14 s

Explanation:

As we know that total energy of SHM is given by the formula

$E = \frac{1}{2}m\omega^2 A^2$

so we have

$10^{-3} = \frac{1}{2}(0.200)(\omega A)^2$

so we have

$A\omega = 0.1$

As we know that maximum speed of SHM is given as

$v_{max} = A\omega$

so we have

$v_{max} = 0.1 m/s$

now from above equation we have

$0.05 \omega = 0.1$

$\frac{2\pi}{T} = 2$

$T = \pi s$

#Learn

Topic : SHM

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