The total kinetic energy(in joules) of the molecule in 8g of methane at 27°C?
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Answer:Total kinetic energy = n (3/2 RT0
where n = Number of moles of the gas
R = Gas constant
T = Absolute temperature
Molecular weight of methane,
CH
4
= 12 + 4 * 1 = 16
∴ Number of moles of methane in 8.0 gm of methane
= 8.0/16.0 = 0.5
R = 8.314 joules/K/mole
T = 27 + 273 = 300 K
∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27
o
C = InI * 3/2 RT
= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
∴ Average kinetic energy = 1870.65/6.023 *10
23
*0.5
= 6.21 * 10
-21
joules/molecule
Explanation:
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