Question

The total kinetic energy(in joules) of the molecule in 8g of methane at 27°C?​

Answer 1

Answer:Total kinetic energy = n (3/2 RT0

where n = Number of moles of the gas

R = Gas constant

T = Absolute temperature

Molecular weight of methane,

CH

4

= 12 + 4 * 1 = 16

∴ Number of moles of methane in 8.0 gm of methane

= 8.0/16.0 = 0.5

R = 8.314 joules/K/mole

T = 27 + 273 = 300 K

∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27

o

C = InI * 3/2 RT

= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules

∴ Average kinetic energy = 1870.65/6.023 *10

23

*0.5

= 6.21 * 10

-21

joules/molecule

Explanation: