the total no.of electrons present in 4.6 g of sodium is
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It is 1.20*10^23.This is also from anth
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0.20 mol Na
by using following formula:-
n=m/M,
in which n= # of moles ; m= the mass of the substance ; and M= the molar mass of the substance.
n=4.6 g / 22.99 g/mol = 0.20 mol Na
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