Question

The total no. of lion and peacock in the certain zoo is 50. And no. of their legs is 140. Find the no. of lion and peacock in the zoo.​

Answer 1

Let the number of lion be x and number of peacock be y.

Lion has 4 legs and peacock has 2 legs.

So,

x+y=50----------------------(1)

4x+2y=140----------------(2)

Multiply equation (1) with 2.

2x+2y=100---------------(3)

Subtract equation (3) with (1)

2x=40

x=20

y=50-20=30

So, number of lion is 20 and number of peacock is 30.

Answer 2

Answer:

Step-by-step explanation:Given information,

Total No. of Lions and peacocks = 50

Total No. of Legs of Lion and Peacocks = 140

To find: Number of Lions and Peacock and Lions in Zoo

-------- ------- ------------- -----------

Let

Total number of Lions = x

Total number of peacocks = y

By first condition,

x + y = 50 -------- (i)

By second condition,

As we know that,

Lion has 4 legs and peacock has 2

Therefore, 4x + 2y = 140

Dividing 4x + 2y = 140 by 2,

=> 2x + y = 70 ------ (ii)

From equation (i) and (ii)

x + y = 50

2x + y = 70

_____________

3x = 120

x = 120/3

x = 20

Therefore, Total number of Lions in zoo are 20

And, Number of peacocks in zoo = (50-x)

                                                        = 30

Therefore, Total number of peacocks = 30