Question

the total number of 9 digit number of different digits is

Answer 1

I think it's c
I am not confirm

Answer 2

n!=n(n−1)(n−2)(n−3)......(3)(2)(1)

No of ways of filling first place =9
No of ways of filling remaining 8 place =9×8×7×6×5×4×3×29×8×7×6×5×4×3×2
⇒9!⇒9!
Total no of numbers =9×9!9×9!
Hence (C) is the correct answer.