Question

The total number of electrons in 1.6g of ch4 to that in 1.8g of h2o

Answer 1

No of moles of ch4= 1.6/16(molar mass) =0.1
No of electrons in 1 atom of ch4= 10
No of electrons in 0.1 Mol of ch4= 0.1 x 6 x 10^23 x 10= 6 x 10^23 electrons
By using the same method for water, we find that the two compounds have same number of electrons

Answer 2

Answer:

The total number of electrons in 1.6 g of methane to that in 1.8 g of water is 1:1.

Explanation:

Mass of methane = 1.6 g

Moles of methane = $\frac{1.6 g}{16 g/mol}=0.1 mol$

Number of molecules of methane = $0.1 mol\time N_A$

In 1 molecule of methane = 10 $e^-$

Total number electrons in 1.6 g = $T=10\times 0.1\times N_A$..(1)

Mass of water= 1.8 g

Moles of methane = $\frac{1.8 g}{18 g/mol}=0.1 mol$

Number of molecules of methane = $0.1 mol\time N_A$

In 1 molecule of methane = 10 $e^-$

Total number electrons in 1.8 g = $T'=10\times 0.1\times N_A$..(2)

Dividing (1) by (2)

$\frac{T}{T'}=\frac{10\times 0.1\times N_A}{10\times 0.1\times N_A}=\frac{1}{1}$

The total number of electrons in 1.6 g of methane to that in 1.8 g of water is 1:1.