the total number of electrons in 4.2g of N3- ion is(NA IS THE AVAGARDO NO.)
1)2.1 NA
2)4.2 NA
3)3NA
4)3.2NA
Answers
Answered by
571
Nitrogen-Symbol-N -7(atomic number)
N³⁻ ion = 1s²2s²2p⁶
Total number of electrons =10
atomic mass of N=14
14g of N³⁻ ion contains 10NA electrons
where NA - Avagadro number
so, 1 g of N³⁻ ion =10NA/14
∴4.2g of N³⁻ ion =4.2x 10NA/14
=3NA
∴The total number of electrons in 4.2g of N3- ion 3NA ---- option (3)is correct
N³⁻ ion = 1s²2s²2p⁶
Total number of electrons =10
atomic mass of N=14
14g of N³⁻ ion contains 10NA electrons
where NA - Avagadro number
so, 1 g of N³⁻ ion =10NA/14
∴4.2g of N³⁻ ion =4.2x 10NA/14
=3NA
∴The total number of electrons in 4.2g of N3- ion 3NA ---- option (3)is correct
Answered by
122
Answer:N3- has 10 electrons
Therefore,
Mole = weight / atomic mass
= 4.2 / 14
= 0.3
No. Of mole = 0.3 × 10
= 3
Total no. Of electron = 3× Na
= 3Na
Explanation: therefore, option(c) is correct...
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