Question

the total number of electrons in the human body is typically in order of 10^28.suppose due to some reason you and your friend lost one % of this number of electrons calculate the electrostatic force between you and your friend separated at a d=1m compare this with your weight assume mass of each person is 60kg and use point charge approximation

Answer 1

10^26 electrons are lost, so the bodies now have a charge of:

+ 1.6 * 10^(-19) * 10^26 C = + 1.6 * 10^7 C

ESFA = kq²/r² (charge on both the bodies is same)

= 9 * 10^9 * (1.6)² * 10^14 / 1² N = 9 * 2.56 * 10^23 N = 2.304 * 10^24 N.

Weight = 60 * 10 = 600 N.

Ratio of ESFA and weight = 2.304 * 10^24 / 600 = 0.384 * 10^22 = 3.84 * 10^21.