Question

The total number of elimination product(s)(including stereoisomers) in the given reaction is/are PhCH2CH(Br) CH2Ph NaNH2/∆ Product(s) 1 2 3 4

Answer 1

Answer:

$phch2ch(br)ch2ph \: nanh2 | \: \: = > heat \: \: \: \: product(s)1234$

Answer 2

Correct answer is 4

Explanation:

• The total number of elimination product(s)(including stereoisomers) in $PhCH2CH(Br) CH2Ph$  is 1+2+1 that is 4
• Isomers which differ in the spatial arrangement of atoms are known as Stereoisomers.
• They are of the order of atomic connectivity.
• Such type of isomers have the most interesting type of isomer which is the mirror-image stereoisomers.
• These stereoisomers are a non-superimposable set that consists of  two molecules that are the mirror image of one another.
• They are also known as the spatial isomerism.
• In this form of isomerism molecules have the same molecular formula.

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