Question

The total number of integers between 100 and 200, wch are divisible by both 9 and 6, is:

Answer 1

LCM of 6 and 9: 18

>6=2*3

>9=3*3

What is the highest multiple of 18 under 100?

>200-100=100

90 = 18*5

Calculate the first starting position, 108

>108=18*6

If 108 + 90 < 200 AND 200–(108+90) < 18

then 90/18 is the answer.

The answer is 5

Answer 2

Answer:

6

Step-by-step explanation:

LCM of 9 and 6 = 18

Multiples of 18 will be divisible by both 9 and 6.

First no. divisible by 18 between 100 and 200 = 108

Last no. divisible by 18 between 100 and 200 = 198

Difference = 18

No. of term  = (Last no. − First No.)/difference+1

= (198−108)/18+1

=90/18+1

=5+1

=6