Question

The total number of moles of O2 in 5600 ml O2 gas at STP is what

Answer 1

Answer: Volume of any gas at STP is 22.4L. So,

No. of moles at ginen volume = n

n = Given volume / Molar volume

n = 5.6/22.4 = 0.25.

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Answer 2

The number of moles in 5600 ml of  O₂ gas  is 0.25 moles

Step by step explanation:

Given details :

Volume of O₂ gas = 5600 ml

(at STP)

To find

Number of moles n

$\textbf{\large According to Avogadro's law :}$

Equal volume of every gases, at the same temperature and pressure,

has the same number of molecules.

It means Volume is directly proportional to number of molecules (or moles),

(at same pressure and temperature)

It means

$\frac{\text{\Large V}_1}{\text{\Large V}_2} = \frac{\text{\Large N}_1}{\text{\Large N}_2}$

where V is the volume and N is the number of moles of objects.

$\textbf{\Large Standard temperature and Pressure (STP) :}$

Standard conditions for temperature and pressure for experiments and measurements are called STP.

At STP

Temperature = 273 K

Pressure = 1 atm

Volume =22.4 L (molar volume)      (at 22.4 L volume of any gas, the number of moles of all gases is 1  at STP)

So, 22.4 L = 22400  ml gas has 1 mole of O₂ molecules.

Then according to avogadro's law

$\frac{\textbf{\Large 5600}}{\textbf{\Large 22400}} = \frac{\textbf{\Large N}_1}{\textbf{\Large 1}}$

$\frac{\textbf{\Large N}_1}{\textbf{\Large 1}} = \frac{\textbf{\Large 1}}{\textbf{\Large 4}}$

$\textbf{\Large So, The number of moles in 5600 ml gas of O}_2\textbf{\Large = 0.25 moles}$