The total number of moles present in 111 g of cacl2 is
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no. of moles of CaCl2 = 111/111 = 1 mole, ......
no. of molecules of CaCl2 = 1 x No = 6.023 x 1023 molecule
CaCl2 ----------- Ca+ + 2Cl-
1 molecule gives 3 ions
6.023 x 1023 molecules give ions = 3 x 6.023 x 1023 = 18.069 x 1023 ions
no. of molecules of CaCl2 = 1 x No = 6.023 x 1023 molecule
CaCl2 ----------- Ca+ + 2Cl-
1 molecule gives 3 ions
6.023 x 1023 molecules give ions = 3 x 6.023 x 1023 = 18.069 x 1023 ions
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