Math, asked by kunalsinha2711, 1 year ago

The total number of spherical bullets, each of diameter 5 decimeter, that can be made by utilizing the maximum of a rectangular block of lead with 11 metre length 10 metre breadth and 5 metre width is

Answers

Answered by Deepakshrivas
1
volume of cuboid/ volume of sphere =no. of leads. so


11*10*5*3*7*8*1000/22*4*5. =8400
Answered by tardymanchester
1

Answer:

The number of bullets are 8400.

Step-by-step explanation:

Given : The total number of spherical bullets, each of diameter 5 decimeter, that can be made by utilizing the maximum of a rectangular block of lead with 11 metre length 10 metre breadth and 5 metre width.

To find : The number of bullets used?

Solution :

Dimension of a rectangular box is

l=11 m, b=10 m, h=5 m

Volume of the rectangular box is

V_b=l\times b\times h

V_b=11\times 10\times 5

V_b=550m^3

Convert into decimeter,

V=550\times 1000=550000dm^3

Dimension of the bullet,

Diameter = 5 dm , Radius = 5/2 dm.

Volume of the sphere is

V_s=\frac{4}{3}\pi r^3

V_s=\frac{4}{3}\times \frac{22}{7}\times \frac{5}{2}\times \frac{5}{2}\times \frac{5}{2}

V_s=65.47dm^3

Number of bullets is volume of box divided by volume of sphere.

n=\frac{V_b}{V_s}

n=\frac{550000}{65.47}

n=8400.7

Approximately The number of bullets are 8400.

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