The total number of ways in which 11 identical apples can be distributed among 6 children
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Answered by
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11C6
nCr=n!/(n-r)! *r!
11C6=11!/(11-6)!*6!
=11*10*9*8*7*6!/5!*6!
=11*10*9*8*7/5*4*3*2*1
=462
nCr=n!/(n-r)! *r!
11C6=11!/(11-6)!*6!
=11*10*9*8*7*6!/5!*6!
=11*10*9*8*7/5*4*3*2*1
=462
Answered by
0
Answer:
Step-by-step explanation:
first divide the apples : Apples can be divided in 11C6 ways i.e 462 (since the are idnetical)
Distribution: now each person can receive an apple in 11C6×6!
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