Physics, asked by sandyyd2669, 1 year ago

The total pressure of a gaseous mixture of 2.8g of n^2, 3.2 g of o^2 and o.5 g of h^2 is 4.5atm. calculate the partial pressure of h^2 gas

Answers

Answered by Mysterioushine
26

\huge {\bold {\underline {\underline{Given : - }}}}

  • Total pressure = 4.5 atm
  • Amount of gases present in mixture are 2.8g of N₂ , 3.2 g of O₂ and 0.5g of H₂

\huge {\bold {\underline {\underline{To \: find: - }}}}

  • Partial pressure of H₂ gas

\huge {\bold {\underline {\underline{Solution : - }}}}

Number of moles of a substance is given by ,

 \large \rm {\underline {\bold {\boxed {\bigstar{ \: |  n =  \dfrac{given \: weight}{gram \: atomic \: weight} }}}}}

a] Given weight of N₂ = 2.8g

Atomic weight of N₂ = 28g

Number of moles of N₂ is ,

 :  \implies \: ({n})_{N_2} =  \frac{2.8}{28}  \\  \\  :  \implies {\bold {\boxed {\pink {(n)_{N_2} = 0.1}}}}

b] Given weight of O₂ = 3.2 g

Atomic weight of O₂ = 32g

  : \implies (n)_{o_2} =  \frac{3.2}{32}  \\  \\  :  \implies {\bold {\boxed {\pink {(n)_{o_2} = 0.1}}}}

c] Given weight of H₂ = 0.5 g

Atomic weight of H₂ = 2

 : \implies \: (n)_{H_2} =  \frac{0.5}{2}  \\  \\   : \implies {\bold {\boxed {\pink{(n)_{H_2} = 0.25}}}}

Total number of moles in the given mixture = 0.1 + 0.1 + 0.25 = 0.45 mol

Mole fraction of the first gas in the mixture is given by,

 \large{\bold {\underline {\boxed {\bigstar{ \:  | m =  \dfrac{number \: of \: moles \: of \: the \: first \: gas}{total \: number \: of \: moles \: in \: the \: mixture} }}}}}

Mole fraction of H₂ is ,

 :  \implies \: (m)_{H_2} =  \dfrac{0.25}{0.45}  \\  \\  :  \implies {\bold {\boxed {\pink{ (m)_{H_2} = 0.5}}}}

We have ,

  • Mole fraction of H₂ = 0.5
  • Total pressure in the mixture = 4.5 atm

Partial pressure of any gas in the mixture is given by,

 \large \rm{\underline {\bold {\boxed {\bigstar{ | p = m  \times \:P }}}}}

Where ,

  • p is partial pressure
  • m is mole fraction of the certain gas
  • P is total pressure in the mixture

Partial pressure of H₂ is ,

 :  \implies \: (p)_{H_2} = 0.5 \times 4.5 \\  \\  :  \implies \: (p)_{H_2} = 2.25 \: atm

∴ The partial pressure of H₂ in the given mixture is 2.25 atm

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