Question

The total sum of terms of an AP 3+8+13+18+--------+103 *​

Answer 1

Answer:

The given sequence is 3, 8, 13, 18, ....78.

'a' = 3, 'd' = 5, last term = 78, 'n' = ?

tn=a+(n−1)d⟹78=3+(n−1)5⟹78=3+5n−5⟹78=5n−2⟹5n=80orn=16.

The 16th term is 78.

Answer 2

$\huge\fbox\red{Solution༉}$

Given :-

3 + 8 + 13 + 18 + _____ + 103

To find :-

The given sequence is 3, 8, 13, 18, ....103

'a' = 3, 'd' = 5, last term = 103, 'n' = ?

Find :-

t n

=a +(n−1)d

⟹ 103 = 3 + (n−1) 5

⟹ 103 = 3 + 5n − 5

Then :-

⟹ 103 = 5n − 2

⟹ 5n = 51 or n

Final answer :-

= 16.

$\huge\colorbox{pink}{Thank you ❤}$