the total surface area of a cylinder is 2464 sq cm the height and radius of the cylinder are equal find the radius of its base
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Answered by
0
TSA = 2464
2 pi r(h+r) = 2464
=> 2*22*r(r+r)/7 = 2464
=> r*2r = 2464*7/44
=> 2r^2 = 56*7
=> r^2 = 28*7
=> r^2 = 2*2*7*7
=> r = 2*7
=> r = 14 cm
Radius of Base = 14 cm
2 pi r(h+r) = 2464
=> 2*22*r(r+r)/7 = 2464
=> r*2r = 2464*7/44
=> 2r^2 = 56*7
=> r^2 = 28*7
=> r^2 = 2*2*7*7
=> r = 2*7
=> r = 14 cm
Radius of Base = 14 cm
Answered by
1
h=r
TSA=2*pi*r(r+h)
2464=44/7*r(2r)
2464=44/7*2r^2
2464=88r^2/7
2464*7/88=r^2
196=r^2
root 196=r
14=r
height=radius=14cm
TSA=2*pi*r(r+h)
2464=44/7*r(2r)
2464=44/7*2r^2
2464=88r^2/7
2464*7/88=r^2
196=r^2
root 196=r
14=r
height=radius=14cm
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