Question

The total surface area of a cylinder is 2464sq cm. The height and radius of the cylinder are eqal . Find the radius of it's base.
I want with explanation

Answer 1

tsa = 2464 sq cm
but formula of tsa of cylinder is = 2πr(h+r)
Therefore , 2πr(h+r) = 2464
it is given that h=r
now , 2πr×2r= 2464
2r^2= 2464/2π
r^2= 2464/2×2π
r^2 = 616×7/22
r^2= 28×7
r= √196
r= 14
hence h= r = 14 ans.

Answer 2

Given that TSA of a cylinder = 2464cm^2.

We know that TSA of a cylinder = 2piR(R + H).

Given that height and radius of the cylinder are equal.

2464 = 2 * pi * R(R + R)

2464 = 2 * 22/7 * 2R^2

2464 * 7 = 2 * 22 * 2R^2

17248 = 88R^2

17248/44 = R^2

196 = R^2

R = 14cm.


Therefore the radius of its base = 14cm.


Hope this helps!