Question

the
tower
Stone progected vertically up from the top of
tower a velocity of 19.6 ms' reaches
it's foot in 6s
find the height of
the tower and velocity with which the stone reaches
the ground (g=9.8m/s^2)
​

Answer 1

Answer:

u=19.6m/s

t=6s

a=-g=-9.8m/s^2

Displacement of the ball=-h

Applying s=ut+(at^2)/2

-h=19.6(6)+(-9.8)(36)/2

h=58.8m