The traffic lights at three different road crossings change after every 48 seconds, 72
seconds and 108 seconds respectively. If they change simultaneously at
7 sm. at what time will they change simultaneously again?
Answers
Answer:
7:07:12 a.m
Step-by-step explanation:
The traffic light at three different road crossing change after every 48 seconds,72 seconds and 108 seconds respectively.
So let us take the LCM of the given time that is 48 seconds, 72 seconds, 108 seconds
⇒ 48 = 2 × 2 × 2 × 2 × 3
⇒ 72 = 2 × 2 × 2 × 3 × 3
⇒ 108 = 2 × 2 × 3 × 3 × 3
Hence LCM of 48, 72 and 108 = (2 × 2 × 2 × 2 × 3 × 3 × 3)
LCM of 48, 72 and 108 = 432
So after 432 seconds they will change simultaneously
We know that
60 seconds = 1 minute
so on dividing 432 / 60 we get 7 as quotient and 12 as reminder
Hence, 432 seconds = 7 min 12 seconds
∴ The time = 7 a.m. + 7 minutes 12 seconds
Hence the lights change simultaneously at 7:07:12 a.m
Step-by-step explanation:
The traffic light at three different road crossing change after every 48seconds,72seconds and 108seconds respectively
So,
48=2×2×2×2×3
72=2×2×2×3×3
108=2×2×3×3×3
Therefore, L.CM of 48,72,108 is
(2×2×2×2×3×3×3)
=432
So, time when they change again =432seconds
But we need to find time after 7am So, first we convert 432seconds into minutes.
Time=432second
=
60
432
minutes
∴Time=7 minutes12 seconds
Thus,
Required time =7am+7minutes 12seconds
=7:07:12am
well I helped you
pls mark me the brainleist