Question

The train start from rest and attains 40km/hr velocity in 10seconds . calculate the acceleration of train in km/hr^ 2 and m/s^2.

Answer 1

u=0 m/s
v=40 km/hr
=40×5/18
=11.111 m/s
t=10 s
a=(v-u)/t
a=11.111/10
a=1.111 m/s^2

Answer 2

a=(v-u)/t
where a=acceleration,v=final velocity, u=initial velocity

Here, u =0m/s
v=40km/hr or 40×1000/3600=40×5/18=200/18
=100/9m/s

In km/hr^s:-

a=40/10
=4km/hr^2

In m/s^2:-

a=(100/9)/10
=100/90m/s^2
=10/9m/s^2


Answer:-. In km/hr^2=4km/hr^2
In m/s^2=10/9m/s^2

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