Question

The trajectory of a projectile launched from ground is given by the equation y = -0.025 x2 + 0.5 x, where x and y are the coordinate of the projectile on a rectangular system of axes.
a) Find the initial velocity and the angle at which the projectile is launched.

Answer 1

Answer:

The standard equation of a trajectory is,

$\displaystyle\longrightarrow\sf{y=x\tan\theta-\dfrac{\tan\theta}{R}\ x^2}$

Given equation is,

$\displaystyle\longrightarrow\sf{y=0.5x-0.025x^2}$

Comparing it with the standard one, we get,

$\displaystyle\longrightarrow\sf{\tan\theta=0.5}$

$\displaystyle\longrightarrow\sf{\underline{\underline{\theta=\tan^{-1}(0.5)}}}$

Answer 2

Answer:

The standard equation of a trajectory is,

longrightarrow y=x tan theta- tan theta R x^ 2

Given equation is,

longrightarrow y=0.5x-0.025x^ 2

Comparing it with the standard one, we get,

Rightarrow tan theta=0.5

theta = arctan(0.5)