The transformed equation of 2x² + 4xy + 5y^2 - 4x - 22y + 7 = 0 when the axes are translated to the point (-2, 3) is
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The transformed equation of 2x² + 4xy + 5y^2 - 4x - 22y + 7 = 0 when the axes are translated to the point (-2, 3) is midpoint.
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Step-by-step explanation: when axes are rotated (not shifting origin)
we have x= X+h and y= Y+k
x= X-2 and y= Y+3 now substituting these in given equation
2(X-2)²+4(X-2)(Y+3)+5(Y+3)²-4(X-2)-22(Y+3)+7=0
2(x²+4-4x)+4(xy+3x-2y-6)+5(y²+9+6y)-4x+8-22y-66+7=0
2x²+8-8x+4xy+12x-8y-24+5y²+45+30y-4x-22y-51=0
2x²+5y²+4xy-22=0
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