The triangle is 24ft tall and the hypotenuse is 26ft, how do you find the area?
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By Pythogoras theorem.
a^2+b^2=h^2
h^2-a^2=b^2
(26^2-24^2)=b^2
(676-576)=b^2
100=b^2
b=√100=10
Area of ∆=1/2 × b× h
=1/2 × 10×24
=240/2
=120 sq.units
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