Math, asked by saniaali85, 11 months ago

The triangular side walls of a flyover have been used for advertisements. The sides of the walls have lengths 100m, 35m and 105m. The rent per year for the advertisements is Rs. 4000 per m². A company hired one of its walls for 2 months. How much rent did it pay ? (√34 ≅ 5.83)

Answers

Answered by hukam0685
9

Answer:

Company have to pay 11,66,000 Rs as rent for 2 months.

Step-by-step explanation:

Area of triangle when all sides are given can be calculated by the Hero's Formula

\boxed{Area \: of \: triangle =  \sqrt{S(S - a)(S - b)(S - c)}}\\  \\

S= Semi-perimeter

a,b,c are sides of triangle

Area of given triangle a=100 m

b= 35 m

c= 105 m

S =  \frac{a + b + c}{2}  \\  \\S  =  \frac{100 + 35 + 105}{2}  \\  \\S  = 120 \\  \\

Area of Triangle

 =  \sqrt{120(120 - 100)(120 - 35)(120 - 105}  \\  \\  =  \sqrt{120 \times 20 \times 85 \times15 }  \\  \\  =  \sqrt{3060000}  \\ \\=300 \sqrt{34}\\ \\  = 1749 \:  {m}^{2}  \\  \\

Total rent of the site per year=

 = 4000 \times 1749 \\  \\  = 6996000\: Rs \\  \\

Rent of site per 2 month

 =  \frac{6996000}{6}  \\  \\  = 1,166,000 \: Rs \\  \\

Hope it helps you.

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