Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls have lengths 100m, 35m and 105m. The rent per year for the advertisements is Rs. 4000 per m². A company hired one of its walls for 2 months. How much rent did it pay ? (√34 ≅ 5.83)

Answer 1

Answer:

Company have to pay 11,66,000 Rs as rent for 2 months.

Step-by-step explanation:

Area of triangle when all sides are given can be calculated by the Hero's Formula

$\boxed{Area \: of \: triangle = \sqrt{S(S - a)(S - b)(S - c)}}$

S= Semi-perimeter

a,b,c are sides of triangle

Area of given triangle a=100 m

b= 35 m

c= 105 m

$S = \frac{a + b + c}{2} \\ \\S = \frac{100 + 35 + 105}{2} \\ \\S = 120$

Area of Triangle

$= \sqrt{120(120 - 100)(120 - 35)(120 - 105} \\ \\ = \sqrt{120 \times 20 \times 85 \times15 } \\ \\ = \sqrt{3060000} \\ \\=300 \sqrt{34}\\ \\ = 1749 \: {m}^{2}$

Total rent of the site per year=

$= 4000 \times 1749 \\ \\ = 6996000\: Rs$

Rent of site per 2 month

$= \frac{6996000}{6} \\ \\ = 1,166,000 \: Rs$

Hope it helps you.