Question

The triangular side walls of a flyover have been used for advertisements. The sides

of the walls are 13m, 14m and 15m. The advertisements yield an earning of Rs.

2000 per m2

a year. A company hired one of its walls for 6 months. How much

rent did it pay?​

Answer 1

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Answer 2

Answer:

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Step-by-step explanation:

GIVEN:-

a=13m

b=14m

c=15m

SEMI-PERIMETER OF THE TRIANGLE,s=(13+14+15)/2=21m

USING HERON'S FORMULA,

AREA=√[s(s-a)(s-b)(s-c)]

          =√[21*(21-13)*(21-14)*(21-15)]

          =√[21*8*7*6]

          =√7056

AREA =84 m^{2}m2

since,1 m^{2}m2 costs Rs.2000 per year

therefore,84m^{2}m2 will cost 2000*84,that is Rs168000 per year

therefore for 6 months,i.e.1/2 year,it will cost

                                                     =168000*\frac{1}{2}21

                                                     =Rs.84000

THUS,THE COMPANY WILL HAVE TO PAY Rs.84000 AS RENT.