Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 48 m, 14 m and 50 m. The advertisements yield an earning of ₹ 1000 per m2. A company hired one of its walls. How much rent did it pay?

Answer 1

Answer:

Refer figure,

In △ABC

a=122m,b=22m,c=120m

s=

2

a+b+c

=

2

122+22+120

=132m

ar△ABC=

s(s−a)(s−b)(s−c)

=

132(132−122)(132−23)(132−120)

=

132×10×110×12

=

132×10×11×10×12

=

(132)

2

×(10)

2

=132×10=1320 m

2

Rent of 1 m

2

per year = Rs. 5000

Rent of 1 m

2

per month = Rs.

12

5000

Rent of 1 m

2

for 3 months=Rs.

12

3×5000

Rent of 1320 m

2

for 3 months=Rs. (

12

3×5000×1320

)

= Rs.16,500,000

Step-by-step explanation:

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