Question

The trinomial p(x)=x^3-x has three real zeros. true or false ​

Answer 1

True.

Taking y as 0 (finding x-intercept):

x^3 - x = 0

=> x(x^2 - 1) = 0

=> x = 0 OR x^2 - 1 = 0

=> x = 0 OR x^2 = 1

=> x = 0 OR x = 1 OR x = -1 [Roots of the function]

The roots of the function make the function have 3 real zeroes.