Question

The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.​

Answer 1

Answer:

Kelvin and Celsius

scales are related as:

TC = TK – 273.15 … (i)

Celsius and Fahrenheit scales are related as:

TF = (9/5)TC + 32 ....(ii)

For neon:

TK = 24.57 K

∴ TC = 24.57 – 273.15 = –248.58°C

TF = (9/5)TC + 32

= (9/5) × (-248.58) +32

= 415.440 F

For carbon dioxide:

TK = 216.55 K

∴ TC= 216.55 – 273.15 = –56.60°C

TF = (9/5)TC + 32

= (9/5) × (-56.60) +32

= -69.880 C

Answer 2

Answer:

Given,

Triple point of Neon (TNeon) = 23.57 K

Triple point of Carbon dioxide (TCarbon dioxide) = 216.55 K

We know,

Tc = Tk – 273.15

Where, Tc is temperature in Celsius scale

Tk is temperature in Kelvin scale

Also,

Tf = (9/5)Tc + 32

Where, Tf is temperature in Fahrenheit scale

For Neon:

Tk = 24.57 K

∴ Tc = Tk – 273.15

⇒ Tc = 23.57 – 273.15

⇒ Tc = -248.58 °C

And Tf = (9/5)Tc + 32

⇒ Tf = (9/5)(-248.58) + 32

⇒ Tf = -447.44 + 32

⇒ Tf = -415.44°F

For Carbon dioxide:

Tk = 216.55 K

∴ Tc = Tk – 273.15

⇒ Tc = 216.55 – 273.15

⇒ Tc = -56.6 °C

And Tf = (9/5)Tc + 32

⇒ Tf = (9/5)(-56.6) + 32

⇒ Tf = -101.88 + 32

⇒ Tf = -69.88 °F

NOTE: The triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium.