The two acids H2S04 & H3PO4 are neutralised separately by the same amount of an alkali
when sulphate & phosphate are formed respectively. Find ratio of the masses of H2S04 & H3PO4
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Answer:
H
2
SO
4
+2NaOH→Na
2
SO
4
+2H
2
O
H
3
PO
4
+NaOH→NaH
2
PO
4
+H
2
O
Equivalent of alkali= 1 g equivalent of H
2
SO
4
=1 g equivalent of H
3
PO
4
The two acids must react in the ratio of their equivalent masses.
Equivalent mass of H
2
SO
4
=
2
98
=49
Equivalent mass of H
3
PO
4
=
1
98
=98
Hence ratio of masses of H
2
SO
4
: H
3
PO
4
=49:98=1:2
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