The two adjacent sides of a rectangle are 2x2-5xy+3z2and -x2+4xy-z2. Find its perimeter.
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let the ABCD be a rectangle having side length= AB=CD=2x²-5xy+3z² and breadth= BC=DA=-x²+4xy-z²
perimeter of rectangle= 2 (length+breadth)
=2(2x²-5xy+3z²-x²+4xy-z²)
=2(x²-xy+2z²)
=2x²-2xy+4z²
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let the ABCD be a rectangle having side length= AB=CD=2x²-5xy+3z² and breadth= BC=DA=-x²+4xy-z²
perimeter of rectangle= 2 (length+breadth)
=2(2x²-5xy+3z²-x²+4xy-z²)
=2(x²-xy+2z²)
=2x²-2xy+4z²
_____________________________________
please mark me brainliest
Answered by
2
Answer:
perimeter of rectangle= 2 (length+breadth)
=2(2x²-5xy+3z²-x²+4xy-z²)
=2(x²-xy+2z²)
=2x²-2xy+4z²
Step-by-step explanation:
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