The two adjacent sides of a rectangle are 5x2 - 2y2 and x2 + 2xy Find the perimeter.
(A) 12x2 - 4y2 + xy (B) 12x2 – 4y2 - xy (C) 12x2 - 4y - 8xy (D) 12x2 - 4y2 + 4xy
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Answer:
Correct option is
D)12x2−4y2+4xy
Given adjacent sides of a rectangle are 5x2−2y2 and x2+2xy
we know that the perimeter of a rectangle with adjacent sides a and b is 2×(a+b)
Perimeter=2((5x2−2y2)+(x2+2xy))
=2(6x2−2y2+2xy)
=12x2−4y2+4xy
∴Perimeter=12x2−4y2+4xy
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Answer:
A.48
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