The two adjacent sides of a rectangle at 2 x square - 5 x y + 3 z square and 4 x y minus x square minus z square find its perimeter
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Given :- The two adjacent sides of a rectangle at 2x² - 5xy + 3z² and 4xy - x² - z² . find its perimeter ?
Solution :-
we know that,
- Perimeter of rectangle = 2 * sum of adjacent sides .
so,
→ Perimeter = 2(2x² - 5xy + 3z² + 4xy - x² - z²)
→ Perimeter = 2(2x² - x² + 3z² - z² - 5xy + 4xy)
→ Perimeter = 2(x² + 2z² - xy)
→ Perimeter = (2x² + 4z² - 2xy) (Ans.)
Hence, Perimeter of the given rectangle is (2x² + 4z² - 2xy).
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