the two altitudes of the parallelogram are 5 cm and 6 cm. if the base of first altitude is 12 cm find the base of other attitude.
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Hey
First altitude = 5 cm .
The base to first altitude is = 12 cm .
We know that ,
area of parallelogram
= base * height .
So , area
= ( 5 * 12 ) cm²
= 60 cm² .
Now ,
Second altitude = 6 cm
Let the base to second altitude be x .
So area of parallelogram
= 6 * x ( base * height )
Now ,
we have also calculated area of parallelogram = 60 cm² .
So ,
A/q ,
6 * x = 60
=> x = 60 / 6
=> x = 10 .
So ,
required base of second altitude = 10 cm
thanks :)
First altitude = 5 cm .
The base to first altitude is = 12 cm .
We know that ,
area of parallelogram
= base * height .
So , area
= ( 5 * 12 ) cm²
= 60 cm² .
Now ,
Second altitude = 6 cm
Let the base to second altitude be x .
So area of parallelogram
= 6 * x ( base * height )
Now ,
we have also calculated area of parallelogram = 60 cm² .
So ,
A/q ,
6 * x = 60
=> x = 60 / 6
=> x = 10 .
So ,
required base of second altitude = 10 cm
thanks :)
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