the two bulb of volume 5 litre and 10 litre containing an ideal gas at 9 atm and 6 ATM respectively are connected what is the final pressure in the two bulb if the temperature remains constant
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✌️_______UR ANSWER_______✌️
P1V1 + P2V2 = P(V1 + V2)
5*9 + 10*6 = P(15)
45+60= 15P
105÷15 = P
P = 7 atm
⤴️_____HOPE HELP YOU_____⤴️
✌️_______UR ANSWER_______✌️
P1V1 + P2V2 = P(V1 + V2)
5*9 + 10*6 = P(15)
45+60= 15P
105÷15 = P
P = 7 atm
⤴️_____HOPE HELP YOU_____⤴️
muskan371:
sorry but I understand thank you so much
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4
Answer:
Explanation:P1V1 + P2V2 = P(V1 + V2)
5*9 + 10*6 = P(15)
45+60= 15P
105÷15 = P
P = 7 atm
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