The two head lamps of a car are in parallel. They together consume 48 watts with the help of 6V battery.
The resistance of each bulb is:
1) 0.67 ohm
2) 3.0 ohm
3) 4.0 ohms
4) 1.5 ohms
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The two head lamps of a car are in parallel. Hence, the power consumed by them is
P=P
1
+P
2
=48W
Thus, power consumed by each bulb is 24 W with the help of 6V battery hence, the resistance of each bulb is
R=
P
V
2
............ ( since P=
R
V
2
)
R=
24
6
2
R=
24
36
=
2
3
=1.5Ω
P=P
1
+P
2
=48W
Thus, power consumed by each bulb is 24 W with the help of 6V battery hence, the resistance of each bulb is
R=
P
V
2
............ ( since P=
R
V
2
)
R=
24
6
2
R=
24
36
=
2
3
=1.5Ω
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