Question

The two legs AB and BC of right triangle ABC are in the ratio 1:3. Wh
will be the value of sinC?
(a)1/10 b) 3/10
(d)1/2
7)
(c) 1/3​

Answer 1

Answer:

answer:1/✓10

H²= P² + B²

H=√1+3²

H=✓10

SinC= P/B

=1/✓10

Answer 2

Given - Ratio of AB and BC = 1:3

Find - Value of sin C

Solution - As ratio is given, the lengths of AB and BC will be x and 3x respectively.

Now, finding the hypotenuse AC through Pythagoras theorem.

AC² = AB² + BC²

AC² = x² + (3x)²

AC² = x² + 9x²

AC² = 10x²

AC = x✓10

Now calculating sin C = perpendicular/hypotenuse

Assuming perpendicular to be AB, then

sin C = x/x✓10

sin C = 1/✓10

Hence, (a)1/✓10 is the correct answer.