The two nunber is 3:4 the product of their hcf and lcm is 2028 the sum of the number is solution
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let the number of 3x and 4x.
product of no = hcf ×lcm
3x * 4x = 2028
X^2= 169
X= 13
numbers are 3x = 3×13= 39
4x = 4×13= 52
sum of no = 39+52= 91
product of no = hcf ×lcm
3x * 4x = 2028
X^2= 169
X= 13
numbers are 3x = 3×13= 39
4x = 4×13= 52
sum of no = 39+52= 91
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