Question

The two parallel sides of a trapezium are 10 cm
and 22 cm. If its height is 12 cm, what is its area?​

Answer 1

Answer:

192 cm

Step-by-step explanation:

The formula is 1/2* sum of two sides* distance between them

1/2*(10+22)*12

1/2*32*12

16*12

192 cm.

Answer 2

${\underline {\underline {\huge {\bf { Required \: Answers: } }}}}$

Given:

• Measure of parallel sides $\longrightarrow$ 10 cm and 22 cm

• Height $\longrightarrow$ 12cm

To calculate:

• Area of the trapezium

Calculation:

We know that,

${\underline {\boxed {\large {\bf { Area \: of \: trapezium = \dfrac{1}{2} \times sum \: of \: parallel \: sides \times h} }}}}$

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Substitute the values:

$\bf { :\implies Area = \dfrac{1}{2} \times (10+22) times 12}$

$\bf { :\implies Area = \dfrac{1}{\cancel{2}} \times \cancel{32} \times 12}$

$\bf { :\implies Area = 16 \times 12}$

$\bf { :\implies Area = 192 \: {cm}^{2} }$

So, the area is $\bf { 192 \: {cm}^{2} }$.

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