Math, asked by meghanshi2007, 9 months ago

The two sides of a parallelogram
ABCD are 6 cm and 4 cm the
Theight carresponding to the base CD is 3cm find the area of the parallelogram and also find the height corresponding to the base AD.​

Answers

Answered by jithujilladi6
5

Answer:

Step-by-step explanation:

Area of ||gm= b*h

=6*3=18cm^2

Height corresponding to sideAD=4*x=18

=x=18/4=4.5cm

Answered by Himalaysaikia
1

Answer:

Given : The two sides of the parallelogram ABCD are 6 cm and 4 cm.

To Find :

area of the parallelogram.

Solution :

Refer the attached figure for the diagram of parallelogram ABCD.

The two sides of the parallelogram ABCD,

AB=CD=6 cm

BC=AD=4 cm

Area of the parallelogram is given by,

 \tt{area = base \times height} \\  \tt = ab \times ae \\  \tt = 6 \times 3 \\   \tt= 18 {cm}^{2}

Area of the parallelogram is 18 cm².

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