The two sides of a triangle are equal and angles opposite to them are 40° and x. Find x.
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Answer:
ABC is a given triangle with, AB=AC.
To prove: Angle opposite to AB= Angle
opposite to AC (i.e) ∠C=∠B
Construction: Draw AD perpendicular to BC
∴∠ADB=∠ADC=90
o
Proof:
Consider △ABD and △ACD
AD is common
AB=AC
∴∠ADB=∠ADC=90
o
Hence ∠ABD=∠ACD
∠ABC=∠ACB
∠B=∠C. Hence the proof
This is known as Isosceles triangle theorem
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40°
Step-by-step explanation:
Q.
The two sides of a triangle are equal and angles opposite to them are 40° and x. Find x.
Solution -
You are talking about a isosceles triangle.
A common rule, you should remember -
The opposite angles of equal sides of isosceles triangle are equal.
So here,
40° and x are opposite angles of equal sides of isosceles triangle, (see the attachment)
=> x = 40°
Hence the value of x is 40°
hope it helps.
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