Question

The two sides of the parallelogram ABCD are 6 cm and 4 cm. The height corresponding to the base CD is 3 cm. Find the (i) area of the parallelogram. (ii) the height corresponding to the base AD.

Answer 1

Answer:

area = 12 cm²

height corresponding to the base AD is 2 cm

Step-by-step explanation:

area of parallelogram = base × altitude

= 4 cm × 3cm

= 12 cm²

area = base × altitude

∴ → 6 × h

12/6 = h

h =2 cm

Answer 2

Area of the parallelogram is 18 cm².

The height corresponding to the base AD is $\sqrt{7}$ cm.

Step-by-step explanation:

Given : The two sides of the parallelogram ABCD are 6 cm and 4 cm. The height corresponding to the base CD is 3 cm.

To Find :

(i) area of the parallelogram. (ii) the height corresponding to the base AD.

Solution :

Refer the attached figure for the diagram of parallelogram ABCD.

The two sides of the parallelogram ABCD,

AB=CD=6 cm

BC=AD=4 cm

Height AE=3 cm

(i) Area of the parallelogram is given by,

$A=B\times H$

$A=AB\times AE$

$A=6\times 3$

$A=18\ cm^2$

Area of the parallelogram is 18 cm².

(ii) The height corresponding to the base AD is AF,

In triangle ADF,

AE=FD=3 cm , AD=4 cm

Applying Pythagoras theorem,

$AF^2=AD^2-FD^2$

$AF^2=4^2-3^2$

$AF^2=16-9$

$AF^2=7$

$AF=\sqrt{7}$

The height corresponding to the base AD is $\sqrt{7}$ cm.

#Learn more

Two sides of a parrallelogram ABCD are 6cm and 4cm.The height correspomding to the base CD is 3cm.Find (i) the area of the parallelogram ABCD (ii) the height corresponding to the base AD which is 4cm long

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