Question

The two sides of triangle are 16 CM and 14 CM if perimeter is 48 CM then find the area

Answer 1

Answer:

see I am giving u a hint first solve and then u don't get solution ask me ok

Step-by-step explanation:

firstly by Pythagoras theorem write the equation H^2=B^2+P^2 write their values and when u get answer use this formula

perimeter of triangle= half*base*height then put the value from above equation

Answer 2

Answer:

Let 16 cm be a and 14 cm be b

Let c be the third side

Let P be perimeter

P= 16+14+c

P=30+c

48-30=c

c=18 cm

Semi perimeter (s)= 1/2 of 48= 24 cm

According to Heron's formula,

Area of a triangle= √s(s-a)(s-b)(s-c)

Area= √24(24-16)(24-14)(24-18)

Area=√24*8*10*6

Area=√144*√80

Area=12*√16*√5

Area=48√5 cm²