the two tangents from an external point p to a circle with centre O are PA and PB.If
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the two tangents from an external point p to a circle with centre O are PA and PB.If <APB=70 what is the value of < AOB
you want answer in explanation or not
it contains two types of answer one is short and other one is long
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Answered by
52
here is the long answer along with pic.
Short answer is that,
angle AOB + angle APB=180
ang. AOB= 180- ang. APB
ang. AOB =180- 70
ang. AOB = 110°
hope this answer will satisfy you
Short answer is that,
angle AOB + angle APB=180
ang. AOB= 180- ang. APB
ang. AOB =180- 70
ang. AOB = 110°
hope this answer will satisfy you
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thanks a lotttttttt!
its ok
nd thanks for mark it brainliest one
Answered by
7
Given : The two tangents from an external point P to a circle with centre O are PA and PB.
APB = 70°
To Find : ∠ AOB.
Solution:
in Quadrilateral OAPB
∠OAP + ∠APB + ∠OBP + ∠AOB = 360°
∠OAP =∠OBP = 90° as PA and PB are tangents
∠APB = 90°
=> 90° + 70° + 90° + ∠AOB = 360°
=> 250° + ∠AOB = 360°
=> ∠AOB = 110°
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