The two thigh bones (femours ) each of cross sectional area 10 cm square support the upper part of a human body of mass 40 kg . estimate the average pressure sustained by the femours ?
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Answered by
82
Pressure is given as
P=Force/Area
=Mg/area
=40*9.8/10*10 raised to -4
=39.2*10 raised to -4 N/m2
(10cm2=10*10 raised to -4m2
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P=Force/Area
=Mg/area
=40*9.8/10*10 raised to -4
=39.2*10 raised to -4 N/m2
(10cm2=10*10 raised to -4m2
Mark me as brainliest if u like my answer.
Answered by
27
Pressure = Force / Area
= mg / A
= (40 * 9.8) / (10 * 10^-4)
= 392000 Pa
= 392 kPa
Average pressure sustained by the femur is 392 kPa
= mg / A
= (40 * 9.8) / (10 * 10^-4)
= 392000 Pa
= 392 kPa
Average pressure sustained by the femur is 392 kPa
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