Question

the two zeroes of a quadratic polynomial are - 4 and -6 . find the sum of product of the zeroes . what is the value of cofficent b ?
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Answer 1

Answer:

• Sum of the zeros = -10
• Product of zeros = 24
• The value of coefficient b = 10

Step-by-step explanation:

Here

α = -4

β = -6

Sum of the zeros = ( α + β )

= -4 + -6 = -10

Product of zeros = ( αβ )

= -4 * -6 = 24

To find the polynomial = k [ $x^{2}$ - ( α + β )$x$ + ( αβ ) ]

⇒ k [ $x^{2}$ - ( -10 ) + 24 ]

⇒ k [ $x^{2}$ + 10 + 24 ]

Now if k = 1

⇒ 1 [ $x^{2}$ + 10 + 24 ]

⇒ $x^{2}$ + 10 + 24 is the required polynomial.

∴ The value of coefficient b = 10

hope it helps ..