The two zeros of quadratic polynomial are -4 and -6. Find the sum and product of zeros what is the value of coefficient b?
Answers
Answered by
55
Answer:
sum=-4+(-6)=-10
product=-4×-6=24
sum of zeroes=-b/a
-10=-b/1
-10=-b
b=10
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Answered by
6
Given:
The two zeros of a quadratic polynomial are -4 and -6.
To find:
- The sum and product of zeros.
- The value of coefficient b.
Solution:
1) The relation between the coefficient and zeroes of the quadratic equation is given by:
- ax²+bx+c = 0
Let p and q are the zeroes of the given quadratic equation then:
- Sum of zeroes is = p+q = -b/a
- Product of zeroes is = pq = c/a
2) So according to the question
Sum of zeroes is
- -4+(-6)
- -10 = -b/a
- 10 = b/a-------(I)
Product of zeroes is
- -4.-6
- 24 = c/a----------(II)
From the equations (I) and (II)
- a = 1
- b = 10
- c = 24
The sum and product of zeros are -10 and 24 repectively.
The value of coefficient b is 10.
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