Math, asked by amandeepmakkar104, 10 months ago

The two zeros of quadratic polynomial are -4 and -6. Find the sum and product of zeros what is the value of coefficient b?

Answers

Answered by rajekalpana25
55

Answer:

sum=-4+(-6)=-10

product=-4×-6=24

sum of zeroes=-b/a

-10=-b/1

-10=-b

b=10

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Answered by DevendraLal
6

Given:

The two zeros of a quadratic polynomial are -4 and -6.

To find:

  • The sum and product of zeros.
  • The value of coefficient b.

Solution:

1) The relation between the coefficient and zeroes of the quadratic equation is given by:

  • ax²+bx+c = 0

Let p and q are the zeroes of the given quadratic equation then:

  • Sum of zeroes is = p+q = -b/a
  • Product of zeroes is = pq = c/a

2) So according to the question

Sum of zeroes is

  • -4+(-6)
  • -10 = -b/a
  • 10 = b/a-------(I)

Product of zeroes is

  • -4.-6
  • 24 = c/a----------(II)

From the equations (I) and (II)

  • a = 1
  • b = 10
  • c = 24

The sum and product of zeros are -10 and 24 repectively.

The value of coefficient b is 10.

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