Question

The umpire tosses the coin with an initial velocity of 10m/s, in the absence of air resistance, the height the coin will reach will be what?​

Answer 1

$v ^{2} - u ^{2} = 2gh$

in this case the acceleration due to gravity opposes the motion of coin so taking

g = - 9.8

u = 10

v = 0

we get

0 - 100 = 2*(-9.8)*h

-100 = -19.6h

h = 100/19.6

h = 5.1 m

Answer 2

Answer:  5.1m...

Explanation:

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